If the freezing point of 0.1 molal HA ( aq ) is − 0.204 6 ∘ C then pH of the solution is [ k f ( H 2 O ) = 1.8 6 ∘ mol − 1 kg ; assume molality = molarity]

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If the freezing point of 0.1 molal HA ( aq ) is − 0.204 6 ∘ C then pH of the solution is [ k f ​ ( H 2 ​ O ) = 1.8 6 ∘ mol − 1 kg ; assume molality = molarity]

TestHub · Accepted Answer

0.2046 = ( 1 + α ) × 1.86 × 0.1 ⟹ 1 + α = 1.1 ⟹ α = 0.1 [ H + ] = C α = 0.1 × ( 0.1 ) = 1 0 − 2 M p H = 2

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