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ChemistryLiquid SolutionColligative PropertiesMedium2 minQB

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Ratio of $\frac{Δ T _{b}}{K _{b}}$ of $10 g AB_{2}$ and $14 g A_{2} B$ per 100 g of solvent in their respective, solution $(AB_{2}$ and $A_{2} B$ both are non-electrolytes) is $1 mol / kg$ in both cases. Hence, atomic wt. of A and B are respectively :-

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Answer:

Solution:

$Δ T_{b} = K_{b} (\frac{W _{solute}}{W _{solvent}} \times \frac{1}{M _{solute}}) \times 1000$

$11 M_{A B_{2}} similarly M_{A_{2} B} 100140 M_{A} = \frac{1000 \times 10}{100 \times M _{A B_{2}}} = \frac{1000 \times 10}{100 \times M _{A B_{2}}} = 100 = 140 = M_{A} + 2 M_{B} = 2 M_{A} + M_{B} = 60 and M_{B} = 20$

Stream:JEESubject:ChemistryTopic:Liquid SolutionSubtopic:Colligative Properties

⏱ 2mℹ️ Source: QB

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