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ChemistryLiquid SolutionMiscellaneous/MixedEasy2 minPYQ_2020
ChemistryEasynumerical

Depression in freezing point of 0.01 molal aqueous solution of HA is 0.01924K. ThepKavalue of HA is
[Given = molarity = molality, K f H 2 O =1 .85 Kkg mol 1 ,log2=0.3  

Answer:
4.80
Solution:

ΔTf=i×m×Kf
0.01924=i×0.01×1.85
i=1.04
i=1+α(n1)
1.04=1+α(21)
α=0.04
K a = α 2 c= 0.04 2 ×0.01=16× 10 6
pK a =4.8

Stream:NTA_ABHYASSubject:ChemistryTopic:Liquid SolutionSubtopic:Miscellaneous/Mixed
2mℹ️ Source: PYQ_2020

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