Chemistry - Liquid Solution Question with Solution | TestHub

Mass of polymer (W_B) = 1.0 g

Molar mass of polymer (M_B) = 185000 g mol^-1

Volume of solution (V) = 450 mL = 0.450 L

Temperature (T) = 37 + 273 = 310 K

Solution constant (R) = 8.314 x 10³Pa L K^-1mol^-1

Osmotic pressure$\left(\pi \right)=\text{CRT}$

$=\frac{{\text{W}}_{\text{B}}\times \text{R}\times \text{T}}{{\text{M}}_{\text{B}}\times \text{V}}$

$\pi =\frac{\left(\text{1.0}\text{g}\right)\times \left(\text{8.314}\times {\text{10}}^3\text{Pa}{\text{L K}}^{-1}{\text{mol}}^{-1}\right)\times \left(\text{310 K}\right)}{\left({\text{185000 g mol}}^{-1}\right)\times \left(\text{0.450 L}\right)}$

= 30.95 Pa