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ChemistryLiquid SolutionMiscellaneous/MixedMedium2 minQB

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Density of a 2.05 M solution of acetic acid in water is $1.02 g / ml$ . The molality of the solution is (Atomic mass: $H = 1, C = 12, O = 16$ )

Answer:

Solution:

Molality $= \frac{1000 \times M}{1000 \times d - ( M \times M _{1} )}$

$= \frac{1000 \times 2.05}{1000 \times 1.02 - ( 2.05 \times 60 )}$

$= 2.28 m o l k g^{- 1}$

Stream:JEESubject:ChemistryTopic:Liquid SolutionSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: QB

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