Chemistry - Ionic Equilibrium Question with Solution | TestHub

AgI $\rightleftharpoons$ Ag⁺ + I⁻

$ss$

In the presence of $10^{–4}$ N KI, the solubility of AgI decreases due to the common ion effect. Let it be $S^{}$.

AgI $\rightleftharpoons$ Ag⁺ + I⁻

$S^{\prime }(S^{\prime }+10^{–4})$

$K_{sp}=S^{\prime }(S^{\prime }+10^{–4})$

$1\times 10^{–16}=S^{\prime }(S^{\prime }+10^{–4})$

$S^{\prime }=1\times 10^{–12}$ M.