Chemistry - Ionic Equilibrium Question with Solution | TestHub

$\left[\text{I} \right] \left[{\text{Ag}}^{+}\right]=\sqrt{{\text{K}}_{\text{sp}}\left(\text{AgCl}\right)}=\sqrt{1\times 10^{-10}}=10^{-5}\text{M}$

$\left[\text{II}\right] \left[{\text{Ag}}^{+}\right]=\sqrt{{\text{K}}_{\text{sp}}\left(\text{AgI}\right)}=\sqrt{1\times 10^{-16}}=10^{-8}\text{M}$

$\left[\text{III}\right] \left[\text{Ag}{\left({\text{NH}}_3\right)}_2^{+}\right]\rightleftharpoons {\text{Ag}}^{+}+2{\text{NH}}_3$

${\text{K}}_{\text{d}}=1\times 10^{-8}=\frac{\left[{\text{Ag}}^{+}\right]{\left[{\text{NH}}_3\right]}^2}{\text{Ag }{\left[{\text{NH}}_3\right]}_{2_{\text{aq}}}^{+}}=\frac{\left[{\text{Ag}}^{+}\right]0\text{.}{1}^2}{1\text{.}0}\Rightarrow \left[{\text{Ag}}^{+}\right]=1\times 10^{-6}\text{M}$

$\left[\text{IV}\right]\text{ Ag}{\left(\text{CN}\right)}_{2_{\text{(aq)}}}^{-1}\rightleftharpoons {\text{Ag}}_{\left(\text{aq}\right)}^{+}+2{\text{CN}}_{\left(\text{aq}\right)}^{-1}$

$\text{K}\text{CN}\left(0\text{.}1\text{M}\right)⟶{\text{K}}_{\text{aq}}^{+}+ {\text{CN}}_{\text{aq}}^{-1}$
(0.1M)

${\text{K}}_{\text{d}}=1\times 10^{-21}=\frac{\left[{\text{Ag}}^{+}\right]{ \left[{\text{CN}}^{-}\right]}^2}{{\left[\text{Ag }{\left(\text{CN}\right)}_2\right]}^{-1}}=\frac{\left[{\text{Ag}}^{+}\right]{ \left[0\text{.}1\right]}^2}{1\text{.}0}$

[Ag⁺] = 1 x 10^{- 19}M.