If for a binary weak electrolyte the solubility product is 4 × 1 0 - 10 at 298 K . Calculate its solubility in mol d m - 3 at the same temperature

A B ⇌ A + + B - ; K s p = S 2 S = K s p = 4 × 1 0 - 10 = 2 × 1 0 - 5

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Chemistry - Ionic Equilibrium Question with Solution | TestHub

ChemistryIonic EquilibriumSolubility ProductEasy2 minPYQ_2020

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If for a binary weak electrolyte the solubility product is $4 \times 1 0^{- 10}$ at $298 K$ . Calculate its solubility in mol $d m^{- 3}$ at the same temperature

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Answer:

Solution:

$A B ⇌ A^{+} + B^{-}; K_{s p} = S^{2}$
$S = \sqrt{K_{s p}} = \sqrt{4 \times 1 0^{- 10}} = 2 \times 1 0^{- 5}$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Ionic EquilibriumSubtopic:Solubility Product

⏱ 2mℹ️ Source: PYQ_2020

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