Chemistry - Ionic Equilibrium Question with Solution | TestHub

The solubility product constant is the equilibrium constant for the dissolution of a solid substance into an aqueous solution. It is denoted by the symbol ${\mathrm{K}}_{\mathrm{sp}}$.

Solubility of ${\mathrm{CaF}}_2=\mathrm{S} \mathrm{mole}//\mathrm{L}$

$\mathrm{S}=\frac{2.34\times {10}^{-3}}{0.1\times 78}=\frac{2.34}{78}\times {10}^{-2}=3\times {10}^{-4} \mathrm{mol}/\mathrm{L}$

${\mathrm{K}}_{\mathrm{sp}}\left({\mathrm{CaF}}_2\right)=4{ \mathrm{S}}^3=4{\left(3\times {10}^{-4}\right)}^3$

$=108\times {10}^{-12}$

$=0.0108\times {10}^{-8}{\left(\mathrm{mol}/\mathrm{L}\right)}^3$