Chemistry - Ionic Equilibrium Question with Solution | TestHub

$\text{M}\text{.eq}\text{.}\text{of}\text{0}\text{.2}\text{M}{\text{H}}_{\text{2}}{\text{SO}}_{\text{4}}\text{=}\frac{\text{2}\text{×}\text{0}\text{.2}\text{M}}{\text{1000}}\text{×}\text{100}\text{=}\text{0}\text{.04}$

$\text{M}\text{.eq}\text{. of }\text{2}\text{M}\text{NaOH}\text{=}\frac{\text{0}\text{.2}}{\text{1000}}\text{×}\text{100}\text{=}\text{0}\text{.02}$

$\text{milli}\text{moles}\text{of}\left[{\text{H}}^{\text{+}}\right]\text{left}\text{=}\text{0}\text{.04}-\text{0}\text{.02}\text{=}\text{0}\text{.02}$

$\text{Total}\text{volume}{\text{[H}}^{\text{+}}\text{]}\text{=}\text{200}\text{=}\frac{\text{.02}}{\text{200}}\text{=}\text{0}\text{.0001}\text{=}{\text{10}}^{-\text{4}}\text{M}$

$\mathrm{p}\mathrm{H}=4$.