Chemistry - Ionic Equilibrium Question with Solution | TestHub

The solubility of barium iodate in an aqueous solution prepared by mixing 200 mL of 0.010 M barium nitrate with 100 mL of 0.10 M sodium iodate is $X\times 10^{-6}\mathrm{mol}{\mathrm{dm}}^{-3}$. The value of $X$ is . Use: Solubility product constant $\left(K_{\mathrm{sp}}\right)$ of barium iodate $=1.58\times 10^{-9}$