The solubility of P b ( O H ) 2 in pure water is 20 3 × 1 0 - 6 M . Calculate concentration of O H - ion in a buffer solution of P H = 8 .

As pH = 8 So [ H + ] = 1 0 - 8 [ O H - ] = K w [ H + ] [ O H - ] = 1 0 - 14 1 0 - 8 = 1 0 - 6

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Chemistry - Ionic Equilibrium Question with Solution | TestHub

ChemistryIonic EquilibriumMiscellaneous/MixedEasy2 minPYQ_2020

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The solubility of $P b (O H)_{2}$ in pure water is $\frac{20}{3} \times 1 0^{- 6} M$ . Calculate concentration of $O H^{-}$ ion in a buffer solution of $P^{H} = 8$ .

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Answer:

Solution:

As pH = 8
So $[H^{+}] = 1 0^{- 8}$
$[O H^{-}] = \frac{K_{w}}{[H^{+}]}$
$[O H^{-}] = \frac{1 0^{- 14}}{1 0^{- 8}} = 1 0^{- 6}$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Ionic EquilibriumSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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