When 10 mL of 0.1 M acetic acid ( p K a = 5.0 ) is titrated against 10 mL of 0.1 M ammonia solution ( p K b = 5.0 ), the equivalence point occurs at pH

Question

When 10 mL of 0.1 M acetic acid ( p K a ​ = 5.0 ) is titrated against 10 mL of 0.1 M ammonia solution ( p K b ​ = 5.0 ), the equivalence point occurs at pH

TestHub · Accepted Answer

: p K a ​ = − lo g K a ​ , p K b ​ = − lo g K b ​ pH ​ = − 2 1 ​ [ lo g K a ​ + lo g K w ​ − lo g K b ​ ] = − 2 1 ​ [ 5 lo g ( 1 × 1 0 − 14 ) − ( 5 ) ] = − 2 1 ​ [ 5 − 14 − 5 ] = − 2 1 ​ ( − 14 ) = 7 ​

Chemistry - Ionic Equilibrium Question with Solution | TestHub

Options:

Doubts & Discussion