Chemistry - Ionic Equilibrium Question with Solution | TestHub

$\left(\mathrm{p}\right)\mathrm{}$Neither${\mathrm{K}}^{+}$nor$\mathrm{S}{\mathrm{O}}_4^{2-}$ions undergo hydrolysis. So it is neutral.
$\left(\mathrm{q}\right)\mathrm{}$Sodium ions are not hydrolyzed, but acetate ions hydrolyze to form strong base,$\mathrm{O}{\mathrm{H}}^{-}$
$\mathrm{C}{\mathrm{H}}_3\mathrm{C}\mathrm{O}{\mathrm{O}}^{-}+{\mathrm{H}}_2\mathrm{O}\to \underset{\left(\text{weakacid}\right)}{\mathrm{C}{\mathrm{H}}_3\mathrm{C}\mathrm{O}\mathrm{O}\mathrm{H}}+\underset{\left(\text{strongbase}\right)}{\mathrm{O}{\mathrm{H}}^{-}}$
$\left(\mathrm{r}\right)\mathrm{}\mathrm{C}{\mathrm{l}}^{-}$ions are not hydrolyzed.$\mathrm{N}{\mathrm{H}}_4^{+}$hydrolyse to form strong acid,${\mathrm{H}}_3{\mathrm{O}}^{+}$.
$\mathrm{N}{\mathrm{H}}_4^{+}+{\mathrm{H}}_2\mathrm{O}\to \underset{\left(\text{weakbase}\right)}{\mathrm{N}{\mathrm{H}}_3}+\underset{\left(\text{strongacid}\right)}{{\mathrm{H}}_3{\mathrm{O}}^{+}}$
$\left(\mathrm{s}\right)\mathrm{}\mathrm{C}{\mathrm{a}}^{2+}$and$\mathrm{H}\mathrm{C}\mathrm{O}{\mathrm{O}}^{-}$ions are hydrolyzed to form an acid and a base, but the pH cannot be predicted without the knowledge of hydrolysis constants of$\mathrm{C}{\mathrm{a}}^{2+}$and$\mathrm{H}\mathrm{C}\mathrm{O}{\mathrm{O}}^{-}$.