If K sp of Ag 2 CO 3 is 8 × 10 - 12 , the molar solubility of Ag 2 CO 3 in 0 .1 M AgNO 3 is:

(i) (ii) K s p = 8 × 10 − 12 = ( 2 S ′ + 0.1 ) 2 S ′ or S ′ = 8 × 10 − 10 M

Chemistry - Ionic Equilibrium Question with Solution | TestHub

ChemistryIonic EquilibriumSolubility ProductMedium2 minPYQ_2019

ChemistryMediumstatement

If $K_{sp}$ of ${Ag}_{2} {CO}_{3}$ is $8 \times 10^{- 12}$ , the molar solubility of ${Ag}_{2} {CO}_{3}$ in $0 .1 M {AgNO}_{3}$ is:

Answer:

Solution:

(i)

(ii)

$K_{s p} = 8 \times 10^{- 12} = {(2 S^{'} + 0.1)}^{2} S^{'}$

or $S^{'} = 8 \times 10^{- 10} M$

Stream:JEESubject:ChemistryTopic:Ionic EquilibriumSubtopic:Solubility Product

⏱ 2mℹ️ Source: PYQ_2019

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