Chemistry - Ionic Equilibrium Question with Solution | TestHub

ChemistryIonic EquilibriumSolubility ProductMedium2 minQB

ChemistryMediumsingle choice

Passage / Comprehension

To precipitate ions selectively from a mixture, solid AgNO₃ is added slowly without changing the volume to 1 L of solution containing 0.1 mol Cl⁻ and 0.1 mol PO₄³⁻. Take Ksp(AgCl) = 1.2 × 10⁻¹⁰ and Ksp(Ag₃PO₄) = 2.7 × 10⁻¹⁸.

What is the free $C l^{-}$ concentration when $A g_{3} P O_{4}$ starts precipitating?

Options:

Answer:

Solution:

Silver chloride is already at its precipitation equilibrium. At onset of silver phosphate precipitation,

$[C l^{-}] = \frac{K _{s p} ( AgCl )}{[ A g ^{+} ]} = \frac{1.2 \times 1 0 ^{- 10}}{3 \times 1 0 ^{- 6}} = 4 \times 1 0^{- 5} M .$

Stream:JEESubject:ChemistryTopic:Ionic EquilibriumSubtopic:Solubility Product

⏱ 2mℹ️ Source: QB

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