Chemistry - Ionic Equilibrium Question with Solution | TestHub

$\left[{\mathrm{H}}_3{\mathrm{O}}^{+}\right]=1\times 10^{-6}\mathrm{mol}\mathrm{L}{\mathrm{L}}^{-1}$ or $\left[{\mathrm{H}}^{+}\right]=1\times 10^{-6}\mathrm{mol}{\mathrm{L}}^{-1}$ As for distilled water $\left[{\mathrm{H}}^{+}\right]=\left[{\mathrm{OH}}^{-}\right]$ $$\begin{array}{rl}& \left[{\mathrm{H}}^{+}\right]=\left[{\mathrm{OH}}^{-}\right]=1\times 10^{-6}\mathrm{mol}{\mathrm{L}}^{-1}\\ & {\mathrm{K}}_w=\left[{\mathrm{H}}^{+}\right]\left[{\mathrm{OH}}^{-}\right]=10^{-12}{\mathrm{mol}}^2{\mathrm{L}}^{-2}\end{array}$$