Chemistry - Ionic Equilibrium Question with Solution | TestHub

ChemistryIonic EquilibriumBuffer solutionMedium2 minPYQ_2022
ChemistryMediumstatement

50 mL of 0.1 M CH3COOH is being titrated against 0.1 M NaOH. When 25 mL of NaOH has been added, the pH of the solution will be____×10-2. (Nearest integer)

(Given : pKaCH3COOH=4.76)

log2=0.30

log3=0.48

log5=0.69

log7=0.84

log11=1.04

Answer:
476
Solution:

52.500

2.502.52.5

Resultant solution is acidic buffer solution with same concentration of acid and salts.

pH = pKa + log[salt][acid]

So, pH of solution pH=pKa=4.76=476×10-2

Stream:JEESubject:ChemistryTopic:Ionic EquilibriumSubtopic:Buffer solution
2mℹ️ Source: PYQ_2022

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