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Chemistry - Ionic Equilibrium Question with Solution | TestHub

ChemistryIonic EquilibriumTheory of Indicators / Double indicatorEasy2 minPYQ_2020

ChemistryEasysingle choice

What fraction of an indicator (Hln) is in basic form at a pH of 6 if the $p K_{a}$ of the indicator is 5 ?

Options:

Answer:

Solution:

$p H = p K_{a} + l o g \frac{(I n^{-})}{(H I n)}$
$6 = 5 + l o g \frac{(I n^{-})}{(H I n)}$
$\frac{(I n^{-})}{(H I n)} = 10$
$\frac{(I n^{-})}{(I n^{-}) + (H I n)} = \frac{10}{11}$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Ionic EquilibriumSubtopic:Theory of Indicators / Double indicator

⏱ 2mℹ️ Source: PYQ_2020

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