Chemistry - Ideal Gas Question with Solution | TestHub
Two identical vessels are connected by a tube with a valve letting the gas pass from one vessel into the other if the pressure difference, ΔP >= 2.0 atm. Initially there was a vacuum in one vessel while the other contained ideal gas at a temperature 300 K and pressure 4.0 atm. Then both vessels were heated to a temperature 600 K. Up to what value will be the pressure (in atm) in the first vessel (which had a vacuum initially) increase?
Answer:
Solution:
If no gas flowed, the filled vessel would reach 4.0 × 600/300 = 8.0 atm, so the valve opens and gas flows until Delta P = 2.0 atm.
Conservation of moles (vessels identical, volume V each):
4.0V/(R × 300) = P1V/(R × 600) + P2V/(R × 600) ⇒ P1 + P2 = 8.0.
With P2 - P1 = 2.0: P1 = 3.0 atm, P2 = 5.0 atm.
Pressure in the first vessel rises to 3 atm.
