Chemistry - Ideal Gas Question with Solution | TestHub

$u_{mp}=\sqrt{2RT/M}$, so doubling T moves the peak to $\sqrt{2}=1.41$ times the original speed.

The total area under each curve is the same (all molecules), so a curve that is wider must be lower: the peak height falls by the same factor $1/\sqrt{2}=0.71$.

(A) Peaks at the same speed: wrong. (B) Peak at 1.41 times, height 0.71 times: correct. (C) The 600 K curve is taller: wrong. (D) Peak at 2 times the speed (it would need T × 4): wrong.

Answer: (B).