Chemistry - Ideal Gas Question with Solution | TestHub
ChemistryIdeal GasProblems related with container/piston/SPMMedium2 minQB
ChemistryMediummultiple choice
Two identical containers, each of volume Vₒ, are joined by a tube of negligible volume. They contain the same ideal gas at temperature Tₒ and pressure Pₒ. One container is heated to 3Tₒ while the other is kept at Tₒ. If the common pressure becomes P and n is the number of moles of gas in the container at 3Tₒ, then
Options:(select one or more)
Answer:
A, C
Solution:
Moles are conserved: 2PₒVₒ/RTₒ = PVₒ/RTₒ + PVₒ/(3RTₒ) = (4/3)(PVₒ/RTₒ), giving P = 3Pₒ/2. Moles in the hot container: n = PVₒ/(3RTₒ) = (3Pₒ/2)Vₒ/(3RTₒ) = PₒVₒ/2RTₒ. Hence (a) and (c).
Stream:JEESubject:ChemistryTopic:Ideal GasSubtopic:Problems related with container/piston/SPM
⏱ 2mℹ️ Source: QB
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