Chemistry - Ideal Gas Question with Solution | TestHub
ChemistryIdeal GasKinetic Theory of GasesMedium2 minQB
ChemistryMediumsingle choice
Two gases A and B of molecular weights MA and MB are at temperatures TA and TB such that TA/TB = MA/MB. Which of the following has the same value for both the gases?
Options:
Answer:
B
Solution:
(TA)/(TB) = (MA)/(MB) ⇒ (TA)/(MA) = (TB)/(MB), and urms = √(3RT/M) depends only on T/M, so the RMS speeds match. KE per mole (3/2RT) differs when TA ≠ TB; mean free path and pressure depend on N*, which is not fixed. Confirms Ans (b) RMS speed.
Stream:JEESubject:ChemistryTopic:Ideal GasSubtopic:Kinetic Theory of Gases
⏱ 2mℹ️ Source: QB
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