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ChemistryIdeal GasGraham's Law of Diffusion/EffusionMedium2 minQB

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A $4 : 1$ molar mixture of $He & CH_{4}$ kept in a vessel at 20 bar pressure. Due to a hole in the vessel, gas mixture leaks out. What is the composition of mixture effusing out initially?

Options:

Answer:

Solution:

$\frac{r _{He}}{r _{CH_{4}}} = \frac{P _{He}^{0}}{P _{CH_{4}}^{0}} \frac{M _{CH_{4}}}{M _{He}} = \frac{4}{1} \frac{16}{4} = 8 : 1$

Stream:JEESubject:ChemistryTopic:Ideal GasSubtopic:Graham's Law of Diffusion/Effusion

⏱ 2mℹ️ Source: QB

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