Chemistry - Ideal Gas Question with Solution | TestHub

ChemistryIdeal GasKinetic Theory of GasesMedium2 minQB
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One mole of is taken in 1 litre empty container fitted with a movable piston at 300 K . If it is heated to 1200 K at constant pressure then match the change (List-II) in parameters (List-I) of gas as compared to initial state & select the correct code.

List - I

(Parameter)

List - II

(Change)

 

(P) (number of collision made by a molecule per unit time)

(1) 1/8

(Q) (collision frequency) per unit volume per unit time

(2) 2

(R) (mean free path)

(3) 1/2

(S) (root mean square speed)

(4) 4

Options:

Answer:
A
Solution:

At constant pressure, raising T from 300 K to 1200 K makes T2/T1=4.

 

The number density n=P/(kT) becomes one quarter; molecular speed is proportional to sqrt(T) and doubles.

 

(P) Z1 is proportional to n times molecular speed: its final-to-initial ratio is (1/4)(2)=1/2. P matches 3

 

(Q) Z11, collisions per unit volume per unit time, is proportional to n^2 times speed.

 

Its ratio is (1/4)^2 times 2=1/8. Q matches 1.

 

(R) Mean free path is inversely proportional to n; it becomes 4 times larger. R matches 4.

 

(S) RMS speed is proportional to sqrt(T); it doubles. S matches 2.

 

Hence P-3, Q-1, R-4, S-2: option A.

Stream:JEESubject:ChemistryTopic:Ideal GasSubtopic:Kinetic Theory of Gases
⏱ 2mℹ️ Source: QB

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