Chemistry - Ideal Gas Question with Solution | TestHub
ChemistryIdeal GasProblems related with container/piston/SPMHard2 minQB
ChemistryHardnumerical
A rigid cylinder holds 12 kg of a gas at 27° and 20 atm. The gas leaks slowly, and after some time at 57° the pressure reads 12 atm. Find the mass of gas (in kg) that has leaked out. Give the answer correct to two decimal places.
Answer:
5.45
Solution:
Volume is constant, so is proportional to /.
Initial: 20/300 = 0.06667. Final: 12/330 = 0.03636.
Fraction remaining = 0.03636/0.06667 = 6/11 = 0.5455.
Mass left = 12 x 6/11 = 6.545 kg.
Mass leaked = 12 - 6.545 = 5.45 kg.
Answer: 5.45.
Stream:JEESubject:ChemistryTopic:Ideal GasSubtopic:Problems related with container/piston/SPM
⏱ 2mℹ️ Source: QB
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