At the sea level, the dry air mass percentage composition is given as nitrogen gas : 70.0, oxygen gas : 27.0 and argon gas : 3.0. If total pressure is 1.15 atm , then calculate the ratio of followings

Question

At the sea level, the dry air mass percentage composition is given as nitrogen gas : 70.0, oxygen gas : 27.0 and argon gas : 3.0. If total pressure is 1.15 atm , then calculate the ratio of followings respectively :
(i) partial pressure of nitrogen gas to partial pressure of oxygen gas
(ii) partial pressure of oxygen gas to partial pressure of argon gas
(Given : Molar mass of $N, O$ and Ar are 14, 16, and $40 g mol^{- 1}$ respectively)

TestHub · Accepted Answer

Po 2 ​ P N 2 ​ ​ ​ = x O 2 ​ ​ ⋅ P T ​ x N 2 ​ ​ ⋅ P T ​ ​ = n O 2 ​ ​ n N 2 ​ ​ ​ {using Dalton's law of partial pressure} ​ = 27/32 70/28 ​ = 2.96 P Ar ​ P O 2 ​ ​ ​ = n Ar ​ n O 2 ​ ​ ​ = 3/40 27/32 ​ = 11.25 ​

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