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A sample of gas has a volume of V₁ l at temperature t₁ °C. When the temperature of the gas is changed to t₂ °C at constant pressure, the volume of the gas was found to increase by 20%. The percentage increase in temperature (in °C) is

Options:

Answer:
B
Solution:

V₂ = 1.2V₁ ⇒ T₂ = 1.2T₁, so Δ T = 0.2(t₁ + 273). As a percentage of t₁: (0.2(t₁+273))/(t₁)×100 = 20 + 5460/(t₁) %. Matches (b).

Stream:JEESubject:ChemistryTopic:Ideal GasSubtopic:Ideal Gas Equation & problems
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