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Chemistry - Ideal Gas Question with Solution | TestHub

ChemistryIdeal GasProblems related with container/piston/SPMMedium2 minQB

ChemistryMediumsingle choice

Passage / Comprehension

Paragraph for Q.9 to Q.10

The figure shows the initial conditions of a system when all valves are closed.

At $0^{\circ} C$ all valves are opened. Take the reaction $2 H_{2} S (g) + SO_{2} (g) \to 3 S (s) + 2 H_{2} O (l)$ to go to completion.

Assume the manometer is sufficiently long and thin. Neglect the volume of solids and liquid formed, the vapour pressure of water, and the volume of connecting tubes.

Calculate the height difference of the liquid levels in the U-tube manometer.

Options:

Answer:

Solution:

$SO_{2}$ (2 mol) is limiting: it uses 4 mol $H_{2} S$ , leaving 3 mol $H_{2} S$ .

Left side volume $= 44.8 + 22.4 = 67.2 L$ : $P = (3 \times 22.4) /67.2 = 1.0 atm$ . Right side: 1 mol $Ne$ in 44.8 L: $P = 0.5 atm$ .

$Δ P = 0.5 atm = 38 cm Hg$ . Liquid $d = 6.8 g/mL$ is half of 13.6, so $h = 38 \times 2 = 76 cm$ . Answer: (B).

Stream:JEESubject:ChemistryTopic:Ideal GasSubtopic:Problems related with container/piston/SPM

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