For a closed container containing 5 moles of an ideal gas, at constant pressure of 1.642 atm, which graph correctly represents the variation of log $V$ v/s log $T$ where volume is in litre & temp in kelvin (log 2 = 0.30)

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V = n RT / P = (5 x 0.0821/1.642) T = 0.25 T . log V = log T + log 0.25 = log T - 0.60. The line has slope 1 (45°) and a negative intercept of -0.60 on the log V axis. (A) has zero intercept, (B) has a positive intercept, (D) has slope tan 30°. Answer: ( C ).

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