A gas cylinder can with stand a maximum pressure of 15 atm. Pressure inside the gas cylinder at 27°C is 10 atm and room in which cylinder kept catches fire at what temperature cylinder will burst ?

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Question Explanation: Determine the bursting temperature of a gas cylinder.

Concept: Pressure-Temperature Law $(P_{1} / T_{1} = P_{2} / T_{2})$ .

Solution: The cylinder bursts when its internal pressure reaches the maximum with standable limit. By substituting initial conditions and the maximum pressure into the gas law, we find the burst temperature.

$P_{1} = 10 a t m, T_{1} = 27 + 273 = 300 K$

$P_{2} = 15 a t m (b u rs tp ress u re)$

$\frac{10}{300} = \frac{15}{T _{2}}$

$T_{2} = \frac{15 \times 300}{10} = 450 K$

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