Chemistry - Ideal Gas Question with Solution | TestHub
ChemistryIdeal GasKinetic Theory of GasesMedium2 minQB
ChemistryMediumsingle choice
At what temperature does the average translational KE of a molecule in a gas becomes equal to the K.E. of an electron accelerated through a PD of 3 V?
Options:
Answer:
C
Solution:
Electron through 3 V gains KE = eV = (1.6×10-19)(3) = 4.8×10-19 J. Set 3/2kT = 4.8×10-19: T = (2 × 4.8×10-19)/3 × 1.38×10-23 ≈ 2.32×104 K = 23,200 K. Confirms Ans (c).
Stream:JEESubject:ChemistryTopic:Ideal GasSubtopic:Kinetic Theory of Gases
⏱ 2mℹ️ Source: QB
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