Boyle's law: P V = K ⇒ ( d V d P ) T = − V 2 K = − V P And [ d P d ( P V ) ] T = 0 Charles's law: T V = K ⇒ ( d T d V ) P = K = T V Avogadro's law: n V = K = P RT ⇒ ( d n d V ) P , T = P RT Graham's law: r = ( − d t d P ) ∝ d 1

Chemistry - Ideal Gas Question with Solution | TestHub

ChemistryIdeal GasIdeal Gas Equation & problemsMedium2 minQB

ChemistryMediummatching list

Match the columns.

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Answer:

Solution:

Boyle's law: $P V = K \Rightarrow (\frac{d P}{d V})_{T} = - \frac{K}{V ^{2}} = - \frac{P}{V}$ And $[\frac{d ( P V )}{d P}]_{T} = 0$

Charles's law: $\frac{V}{T} = K \Rightarrow (\frac{d V}{d T})_{P} = K = \frac{V}{T}$

Avogadro's law: $\frac{V}{n} = K = \frac{RT}{P} \Rightarrow (\frac{d V}{d n})_{P, T} = \frac{RT}{P}$

Graham's law: $r = (- \frac{d P}{d t}) \propto \frac{1}{d}$

Stream:JEESubject:ChemistryTopic:Ideal GasSubtopic:Ideal Gas Equation & problems

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