Chemistry - Ideal Gas Question with Solution | TestHub
ChemistryIdeal GasIdeal Gas Equation & problemsMedium2 minQB
ChemistryMediumnumerical
A 5.0 l box contains 28.4 g of mixture of gases CxH8 and CxH10. The pressure of the gas mixture at 300 K is 2.46 atm. The analysis of the gas mixture shows that carbon is 84.5%, by mass. The value of x is
Answer:
4.00
Solution:
Total moles n = PV/RT = 2.46 × 5.0/(0.0821 × 300) = 0.50 mol.
Average molar mass = 28.4/0.50 = 56.8 g/mol.
Average moles of C per mole of mixture = x (same x in both hydrocarbons), so carbon mass per mole = 12x.
12x/56.8 = 0.845 ⇒ 12x = 48 ⇒ x = 4. (Mixture of C4H8 and C4H10.)
Stream:JEESubject:ChemistryTopic:Ideal GasSubtopic:Ideal Gas Equation & problems
⏱ 2mℹ️ Source: QB
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