Chemistry - Ideal Gas Question with Solution | TestHub

ChemistryIdeal GasGraham's Law of Diffusion/EffusionMedium2 minQB
ChemistryMediummatching list

Match each change in Column I with its results in Column II (a Column I entry may match more than one Column II entry):

Column I (Change)

Column II (Result)

() temperature of a fixed amount of gas becomes 4 times at constant pressure

(1) volume becomes 4 times

(Q) pressure of a fixed amount of gas becomes 4 times at constant temperature

(2) density becomes one-fourth

() 1 mol of gas is replaced by 1 mol of a gas of 4 times the molar mass (same and )

(3) rate of effusion halves

(S) and of a fixed amount of gas both become 4 times

(4) density becomes 4 times

 

(5) volume unchanged

Choose the option with the correct matching:

Options:

Answer:
D
Solution:

() is proportional to at fixed : volume becomes 4 times (1). Same mass in 4 times the volume: density becomes one-fourth (2).

(Q) = constant: becomes one-fourth, so density becomes 4 times (4).

() 1 mol occupies the same volume at the same and (5). Mass is 4 times, so density is 4 times (4). Rate of effusion is proportional to 1/, so it halves (3).

(S) is proportional to /, which is unchanged: volume unchanged (5). Density = / is also unchanged, so (4) is false.

Correct matching: to 1,2; Q to 4; to 3,4,5; S to 5. Answer: (D).

Stream:JEESubject:ChemistryTopic:Ideal GasSubtopic:Graham's Law of Diffusion/Effusion
⏱ 2mℹ️ Source: QB

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