Chemistry - Ideal Gas Question with Solution | TestHub

${\text{C}}_{\text{v,m}}\text{=}\frac{\text{3}}{\text{2}}\text{R}$(for monoatomic gas)

${\text{C}}_{\text{v,m}}\text{=}\frac{\text{5}}{\text{2}}\text{R}$(for diatomic gas)

for the mixture,${{\text{(C}}_{\text{v,m}}\text{)}}_{\text{mix}}=\frac{\frac{3}{2}\text{R}\times 1+\frac{5}{2}\text{R}\times 1}{1+1}$

$=2\text{R}$

$\therefore {{\text{(C}}_{\text{v,m}}\text{)}}_{\text{mix}}=4\text{cal}$