The root mean square speed of an ideal gas in a closed container of fixed volume is increased from 5 × 1 0 2 m s - 1 to 1 0 3 m s - 1 . Which of the following statement might correctly explain how the change is accomplished?

u r m s = 3 R T M = 3 P V M So u r m s u r m s ' = 5 × 1 0 2 m / s 1 0 3 m / s = 1 2 = 3 P V / M 3 P ' V / M = P P ' 1 4 = P P ' or P ' = 4 P .

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Chemistry - Ideal Gas Question with Solution | TestHub

ChemistryIdeal GasKinetic Theory of GasesEasy2 minPYQ_2020

ChemistryEasysingle choice

The root mean square speed of an ideal gas in a closed container of fixed volume is increased from $5 \times 1 0^{2}$ m $s^{- 1}$ to $1 0^{3}$ m $s^{- 1}$ . Which of the following statement might correctly explain how the change is accomplished?

Options:

Answer:

Solution:

$u_{r m s} = \sqrt{\frac{3 R T}{M}} = \sqrt{\frac{3 P V}{M}}$
So $\frac{u_{r m s}}{u_{r m s}^{'}} = \frac{5 \times 1 0^{2} m / s}{1 0^{3} m / s} = \frac{1}{2}$
$= \sqrt{\frac{3 P V / M}{3 P' V / M}} = \sqrt{\frac{P}{P'}}$
$\frac{1}{4} = \frac{P}{P'}$
or $P' = 4 P .$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Ideal GasSubtopic:Kinetic Theory of Gases

⏱ 2mℹ️ Source: PYQ_2020

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