Some gas is present in ' J ' shape tube and in this case level of mercury in both limbs is same. If mercury is replaced by another liquid having density 4 3 th of the density of liquid Hg

Question

Some gas is present in ' J ' shape tube and in this case level of mercury in both limbs is same. If mercury is replaced by another liquid having density $\frac{3}{4}$ th of the density of liquid Hg , then find the height difference in the longer and smaller limb. Assume that temperature is constant and smaller limb is closed.

(Given : d_Hg = 13.6 g/cc)

TestHub · Accepted Answer

Initially, P g a s ​ = P a t m ​ = 76 c m o f H g . 4 3 ​ × 13.6 × h = 76 × 13.6 h = 3 4 ​ × 76 76 cm ∘ f H g = 3 4 ​ × 76 cm ∘ f l i q u i d But since the pressure of the gas does not change, there should be no difference in height. P g a s ​ = P a t m ​ + h d g P a t m ​ = P a t m ​ + h d g h = 0 .

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