Chemistry - Ideal Gas Question with Solution | TestHub

From ideal gas equation,$\mathrm{P}\mathrm{V}=\mathrm{n}\mathrm{R}\mathrm{T}$
$\mathrm{V}\propto \mathrm{n}$(Hence V and T are constant)
and further, number of mol of gas (n)$\propto$weight of the gas (w)
So$\frac{{\mathrm{P}}_1}{{\mathrm{P}}_2}=\frac{{\mathrm{w}}_1}{{\mathrm{w}}_2}$
or$\frac{10\mathrm{a}\mathrm{t}\mathrm{m}}{8\mathrm{a}\mathrm{t}\mathrm{m}}=\frac{15\mathrm{k}\mathrm{g}}{\mathrm{x}}$
or x = 12 kg
Hence, the gas leaked = 15 – 12 = 3 kg.