Chemistry - Ideal Gas Question with Solution | TestHub

PV = Constant
On differentiating both sides, we get
PdV + VdP = 0
PdV = -VdP
$\frac{\mathrm{d}\mathrm{V}}{\mathrm{d}\mathrm{P}}=-\frac{\mathrm{V}}{\mathrm{P}}$
$\frac{\text{1}}{\text{P}}\text{=}-\frac{\text{1}}{\text{V}}\frac{\text{dV}}{\text{dP}}\text{=}\text{β}$
Since$\mathrm{\beta }=\frac{1}{\mathrm{P}}$; inverse relation result into rectangular hyperbola.