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ChemistryIdeal GasMiscellaneous/MixedMedium2 minPYQ_2016

ChemistryMediumsingle choice

At what temperature, the rate of effusion of $N_{2}$ would be 1.625 times than that of $SO_{2}$ at $5 0^{\circ} C$ ?

Options:

Answer:

Solution:

$r \propto U$ and $U = \frac{3 RT}{M}$ $\frac{r _{1}}{r _{2}} = \frac{T _{1} M _{2}}{T _{2} M _{1}}$ or $\frac{r _{N_{2}}}{r _{SO_{2}}} = \frac{T _{1} \times 64}{323 \times 28} = 1.625$ or $T_{2} = 373 K$

Stream:BITSATSubject:ChemistryTopic:Ideal GasSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2016

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