What is the total pressure in chamber B after sufficient time of opening of valve-I keeping valve- 2 closed.

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Identify system parameters: Opening valve-1 connects chambers A and B, making the total volume $V_{t o t a l} = V_{A} + V_{B} = 6.0 L + 10.0 L = 16.0 L$ .

Apply Dalton's law of partial pressures: Since temperature is constant, the total pressure ( $P_{t o t a l}$ ) is given by $P_{A} V_{A} + P_{B} V_{B} = P_{t o t a l} V_{t o t a l}$ .

Calculate final pressure: Substituting the values gives $(4.1 a t m \times 6.0 L) + (0.82 a t m \times 10.0 L) = P_{t o t a l} \times 16.0 L$ .

Final Result: $24.6 + 8.2 = 16.0 \times P_{t o t a l} ⟹ P_{t o t a l} = \frac{32.8}{16.0} = 2.05atm$ .

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