Chemistry - Ideal Gas Question with Solution | TestHub

For a monatomic gas with only Translational degrees of freedom

$\mathrm{E}{}_{\mathrm{a}}=\frac{3}{2}\mathrm{k}{}_{\mathrm{b}}\mathrm{T}$(Avg K E per molecule)

$E=\frac{3}{2}\mathrm{RT}$(Avg K E per mole)⁡

$\mathrm{U}=\sqrt{\frac{3\mathrm{RT}}{\mathrm{m}}}=\sqrt{\frac{2\mathrm{E}}{\mathrm{m}}}$