To an evacuated vessel with movable piston under external pressure of 1 atm, 0.1 mol of He and 1.0 mol of an unknown compound (vapour pressure 0.68 atm. at 0 ° C ) are introduced. Considering the idea

Question

To an evacuated vessel with movable piston under external pressure of 1 atm, 0.1 mol of He and 1.0 mol of an unknown compound (vapour pressure 0.68 atm. at $0 ° C$ ) are introduced. Considering the ideal gas behaviour, the total volume (in litre) of the gases at $0 ° C$ is close to

Answer:

7.00

Solution:

$P_{H e} = 1 - 0.68 = 0.32 a t m, n = 0.1$

$V = \frac{n R T}{P} = \frac{0.1 \times 0.0821 \times 273}{0.32} = 7$

TestHub · Accepted Answer

P H e = 1 - 0.68 = 0.32 a t m , n = 0.1 V = n R T P = 0.1 × 0.0821 × 273 0.32 = 7

Chemistry - Ideal Gas Question with Solution | TestHub

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