Chemistry - Ideal Gas Question with Solution | TestHub

Using $\mathrm{PM}=\mathrm{dRT}$

$$\begin{gathered} \frac{{\mathrm{P}}_1\mathrm{M}}{{\mathrm{P}}_2\mathrm{M}} = \frac{{\mathrm{d}}_1{\mathrm{RT}}_1}{{\mathrm{d}}_2{\mathrm{RT}}_2} \\ \frac{768}{760} = \frac{1.35\times 303}{{\mathrm{d}}_2\times 273} \\ {\mathrm{d}}_2 = \frac{1.35\times 303\times 760}{273\times 768} \\ {\mathrm{d}}_2 = 1.48 \mathrm{kg}/{\mathrm{m}}^3 \end{gathered}$$