Minimum number of electrons having spin equal to ( − 2 1 ) in Cr is " ____ ".

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Chemistry - GENERAL CHEMISTRY Question with Solution | TestHub

ChemistryGENERAL CHEMISTRYElectronic ConfigurationMedium2 minQB

ChemistryMediuminteger

Minimum number of electrons having spin equal to $(- \frac{1}{2})$ in Cr is " $____$ ".

Answer:

Solution:

The electronic configuration of Cr is $[A r] 3 d^{5} 4 s^{1}$ . This gives 6 unpaired electrons. To minimize electrons with spin $- 1/2$ , maximize those with spin $+ 1/2$ .

Total electrons = 24.

Maximum $+ 1/2$ spin = 15.

Minimum $- 1/2$ spin = $24 - 15 = 9$ .

Stream:JEESubject:ChemistryTopic:GENERAL CHEMISTRYSubtopic:Electronic Configuration

⏱ 2mℹ️ Source: QB

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