Chemistry - GENERAL CHEMISTRY Question with Solution | TestHub

For $n=4$, the possible values for $l$ are $0,1,2,3$.

For each $l$, $m_l$ can take $2l+1$ values.

Total $m_l$ values = $(2(0)+1)+(2(1)+1)+(2(2)+1)+(2(3)+1)$

$=1+3+5+7=16$.

Alternatively, the total number of $m_l$ values for a given $n$ is $n^2$.

For $n=4$, total $m_l$ values = $4^2=16$.