Chemistry - GENERAL CHEMISTRY Question with Solution | TestHub

Phosphorus (P) has electronic configuration $$1s^2,2s^2,2p^{6,}3s^{2,}3p^3$$ Therefore, no valence electron is present in the $3d$ subshell. Fe (III) has electronic configuration : $$\begin{array}{rl}& 3d^{5}4s^0\\ & \mathrm{Cr}(\mathrm{I}):3d^{5}4s^0\\ & \mathrm{Mn}(\mathrm{II}):3d^{5}4s^0\end{array}$$