Imagine a universe in which principal quantum number have same possible value as in our universe except angular quantum number ( ℓ ) can have value from [ 0 , 1 , 2 , …… n + 1 ] . Magnetic quantum num

Question

Imagine a universe in which principal quantum number have same possible value as in our universe except angular quantum number ( $ℓ$ ) can have value from $[0, 1, 2, \dots\dots n + 1]$ .

Magnetic quantum number ( m ) can have value from [ $- (ℓ)$ to $+ (ℓ)$ ] [including zero].

Spin quantum number $(m_{s})$ can have value $= [- \frac{1}{2}, 0, + \frac{1}{2}]$

Now find the maximum number of elements that can be possible in $2^{nd}$ period.

(The other rules, such as Aufbau, Hund's or Pauli has same characteristics as before.)

TestHub · Accepted Answer

n=2 will now have 2s,2p,2d and 2f according to new rules since "l" can have values 0,1,2 and 3.

2nd period will start with 2s and will end on 2p.

since m_s can have 3 values, 2s will have 3 electrons and 2p will have 9 electrons(3 in each orbital).

Hence total 12 elements possible.

Chemistry - GENERAL CHEMISTRY Question with Solution | TestHub

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