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Chemistry - GENERAL CHEMISTRY Question with Solution | TestHub

ChemistryGENERAL CHEMISTRYElectronic ConfigurationEasy2 minPYQ_2022
ChemistryEasysingle choice

The correct decreasing order of energy, for the orbitals having, following set of quantum numbers:

(A) n=3,1=0, m=0

(B) n=4,l=0, m=0

(C) n=3,l=1, m=0

(D) n=3,1=2, m=1

Options:

Answer:
A
Solution:

(A) n+l=3+0=33s

(B) n+l=4+0=44s

(C) n+l=3+1=43p

(D) n+l=3+2=53d

Higher the n+l value, higher the energy of the orbital and if two orbitals have same n+l value, then the orbital with higher n value has higher energy.

Thus: D>B>C>A.

Stream:JEESubject:ChemistryTopic:GENERAL CHEMISTRYSubtopic:Electronic Configuration
2mℹ️ Source: PYQ_2022

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