Chemistry - GENERAL CHEMISTRY Question with Solution | TestHub

(A) $\mathrm{n}+\mathrm{l}=3+0=3$$\Rightarrow 3\mathrm{s}$

(B) $\mathrm{n}+\mathrm{l}=4+0=4$$\Rightarrow 4\mathrm{s}$

(C) $\mathrm{n}+\mathrm{l}=3+1=4$$\Rightarrow 3\mathrm{p}$

(D) $\mathrm{n}+\mathrm{l}=3+2=5$$\Rightarrow 3\mathrm{d}$

Higher the $\mathrm{n}+\mathrm{l}$ value, higher the energy of the orbital and if two orbitals have same $\mathrm{n}+\mathrm{l}$ value, then the orbital with higher $\mathrm{n}$ value has higher energy.

Thus: $\mathrm{D}>\mathrm{B}>\mathrm{C}>\mathrm{A}$.